Split string at a certain point in python

Question

I am trying to split a string at a certain point using python

What I want to do is as follows:

let's say we have a string as

str = "123456789123456789"

I want to break this string in to parts where each part has a length of 5 or less (the last part)

so the output of the above string should look like this:

This is my code I am trying to do this:


            errormsg = "123456789123456789"
            if len(errormsg) > 5 :
                print("yes")
                splitat = 5
                str = errormsg
                l, r = str[:splitat], str[splitat:]
                print("l: " + l)
                print("r: " + r)

                while len(r) > 5:
                    # print("hi")                
                    str = r
                    splitat = 5
                    l, r = str[:splitat], str[splitat:]
                    print("l: " + l)
                    print("r: " + r)

But it gives a weird output like this:


yes
l: 12345
r: 6789123456789
l: 67891
r: 23456789
l: 23456
r: 789

Can someone tell me how to fix this?

you dont say what you want the output to be? so its hard to say how to fix it. The output you gett is because you keep printing the l and r values after you split them but you never store these — Chris Doyle, Dec 31 '19 at 14:56
Does this answer your question? [Split string every nth character?](https://stackoverflow.com/questions/9475241/split-string-every-nth-character) — Frederik Baetens, Dec 31 '19 at 14:59
The reason is that you give the slice for `r` no end position, so it encompasses the rest of the string — C.Nivs, Dec 31 '19 at 15:02
errormsg = "123456789123456789" if len(errormsg) > 5 : print("yes") splitat = 5 str = errormsg l, r = str[:splitat], str[splitat:splitat*2] print("l: " + l) print("r: " + r) while len(str) > 5: # print("hi") splitat = 5 l, r = str[:splitat], str[splitat:splitat*2] str = str[splitat*2:splitat*3] print("l: " + l) print("r: " + r) — , Dec 31 '19 at 15:10

score 2 · Answer 1 · answered Dec 31 '19 at 14:54

2

I'd just use the recipe from the itertools module:

def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx
    args = [iter(iterable)] * n
    return izip_longest(fillvalue=fillvalue, *args)

answered Dec 31 '19 at 14:54

gct

14,100
15
68
107

`izip`? Is this a eulogy for Python 2, which ends tonight? – juanpa.arrivillaga Dec 31 '19 at 15:02
zip if you feel like leaping into the new decade =D – gct Dec 31 '19 at 15:05

score 2 · Accepted Answer · answered Dec 31 '19 at 15:00

2

Try:

str = "123456789123456789"
splitted_string = []

for i in range(0, len(str), 5):
    splitted_string.append(str[i:i+5])

print(splitted_string)

answered Dec 31 '19 at 15:00

Dhaval Taunk

1,662
1
9
17

Split string at a certain point in python

2 Answers2