How to encode hex in Python3?

Question

I'm tring to write equivalent for encode("hex") in python3.

Here what i got:

s = "'"
print(str(s).encode('hex'))
>>27

Tring binascii in Python 2.7:

import binascii

s = "'"
print(binascii.hexlify(str(s)))
>>27

So in Python 2.7 both methods give same result. Now i tring to run this code in Python 3.5:

import binascii

s = "'"
print(binascii.hexlify(str(s)))

>>Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: a bytes-like object is required, not 'str'

After i tried:

import binascii

s = "'"
print(binascii.hexlify(str(s).encode('utf8')))

>>b'27'

But not sure what i have to do next. How to get my 27?

`s` is already a string, so no need to `str` it; instead, as per the message, you need to make it a "bytes-like object". — Scott Hunter, Jan 02 '20 at 15:12

score 1 · Accepted Answer · answered Jan 02 '20 at 15:14

1

You only need to decode it, like this:

binascii.hexlify(str(s).encode('utf8')).decode('utf8')

answered Jan 02 '20 at 15:14

marcos

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How to encode hex in Python3?

1 Answers1