The function is giving a return as none

Question

It should be giving the integer.This is a question on hackerrank - Equal stacks

def equalStacks(h1, h2, h3):
    #
    # Write your code here.
    #
    stackSum = sumOfStack(h1, h2, h3)

    (stackSum1, stackSum2, stackSum3) = stackSum

    if stackSum1 == stackSum2 and stackSum1 == stackSum3:
        return stackSum1

    elif stackSum1 <= stackSum2:
        if stackSum2 > stackSum3:
            equalStacks(h1, h2[1:], h3)
        else:
            equalStacks(h1, h2, h3[1:])

    elif stackSum2 <= stackSum3:
        if stackSum3 > stackSum1:
            equalStacks(h1, h2, h3[1:])
        else:
            equalStacks(h1[1:], h2, h3)
    elif stackSum2 <= stackSum1:
        if stackSum1 > stackSum3:
            equalStacks(h1[1:], h2, h3)
        else:
            equalStacks(h1, h2, h3[1:])
    else:
        return -1



def sumOfStack(h1, h2, h3):
        sumN1 = sum(h1)
        sumN2 = sum(h2)
        sumN3 = sum(h3)
        return [sumN1, sumN2, sumN3]

Test cases are:

The first if statement should return the integer instead it is returning None.

Possible duplicate of: [Why does my recursive python function return None?](https://stackoverflow.com/questions/17778372/why-does-my-recursive-python-function-return-none) — khelwood, Jan 08 '20 at 10:26

score 1 · Accepted Answer · answered Jan 08 '20 at 10:24

1

You're not returning a value in every execution path.

Add return before every time you call equalStacks.

answered Jan 08 '20 at 10:24

goodvibration

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The function is giving a return as none

1 Answers1