Delete Matching Elements in two Arrays - Python

Question

def array_diff(a, b):     
    b_index=0 
    while b_index < len(b):
        for x in range(len(a)): 
            if b[b_index]=a[x]:  
                del a[x]
        b_index+=1
    print(a)

array_diff([1,2,3,4,5,6,6,7],[1,3,6])

causes a runtime error because i am mutating the container while still iterating over it what exactly will be the best practice to delete the matching items and return the list without the items

Initial List [1,2,3,4,5,6,6,7]
Final List [2,4,5,7]

`set(a) ^ set(b)` will print `{2, 4, 5, 7}` – Chris Charley Jan 19 '20 at 02:42 — Chris Charley, Jan 19 '20 at 02:42
set removes duplicates in the list – Atikpui7 Jan 19 '20 at 02:44 — Atikpui7, Jan 19 '20 at 02:44
Yes you are right I hadn't considered that. – Chris Charley Jan 19 '20 at 04:20 — Chris Charley, Jan 19 '20 at 04:20

score 0 · Accepted Answer · answered Jan 19 '20 at 03:03

0

Here is how you can return the result in a new list:

elements = [1, 2, 3, 4, 5, 6, 6, 7]
exclude = [1, 3, 6]
result = [e for e in elements if e not in exclude]
# result == [2, 4, 5, 7]

answered Jan 19 '20 at 03:03

oebilgen

41
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Delete Matching Elements in two Arrays - Python

1 Answers1