How to define regular expression in java which accepts only those words which starts and end with a
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1Something like this should work for you `\b(\w)\w+\1\b` for starts and ends with same letter (your question title). If you mean starts and ends with "a" specifically: `\ba\w+a\b` – CrayonViolent Jan 23 '20 at 18:49
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yes it is working, can you explain how it is working – Mayur Jan 23 '20 at 18:51
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Sure! See answer, since it required more info than comment limit – CrayonViolent Jan 23 '20 at 18:55
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This did not deserve to be closed. The linked answer provides info on how to read a pattern. It does not answer the actual question posted. – CrayonViolent Jan 24 '20 at 22:24
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Something like this should work for you \b(\w)\w+\1\b for starts and ends with same letter (your question title).
Explanation:
\b signifies a word boundary - basically anything \w would not match.
(\w) match a single word character and captures it to group 1.
\w+ matches for one or more word characters (to match the rest of the word)
\1 is a back reference to what the capture group 1 matched, to ensure last letter is same as first
CrayonViolent
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