Python - Using if statement, + while condition | Print integers, break when having digits

Question

Question: Write a program to accept integer inputs until the user inputs a non‐integer. Then, the program prints the summation of the inputted numbers.

My code:

Total = 0
Count = 0
while True:
    n = input ('Enter integers')

    if (n.isdigit() == True):
        print (n)
    else:
        break
    n = int(n)    
    total = total + n
    count = count + 1
    sum = sum(total)

I could run the integers, but it fails to break when digits are typed... Anyone knows why? Also I am expecting the sum function to work but it couldn't add together the integers I input.

Thanks!

Unrelated, but you can't use `sum` both as the name of your running-total variable *and* the name of the built-in function. — chepner, Feb 12 '20 at 16:46
what is the exact message/error that you get? Note that your variable names here seem to be inconsistent, `Total` and `total` — Paritosh Singh, Feb 12 '20 at 16:46
Keep the code in the question as text; don't link to an image of your editor/ide/whatever. — chepner, Feb 12 '20 at 16:46
@ParitoshSingh I didn't get an error. I just didn't get the result I need.. Oh thanks, should use capitalized "T" — Ching Long LEE, Feb 12 '20 at 16:47
One of many small issues: [How can I read inputs as numbers?](https://stackoverflow.com/questions/20449427/how-can-i-read-inputs-as-numbers) — G. Anderson, Feb 12 '20 at 16:51
How about summation? Do I change it to any variable say d = sum(Total) print (d) — Ching Long LEE, Feb 12 '20 at 16:51
@EricPetersen, int(n) would raise an exception for non-integers — Don, Feb 12 '20 at 16:52
"but it fails to break when digits are typed" not sure what you mean, your code breaks when something else is typed, not if digits are typed. — njzk2, Feb 12 '20 at 17:00
maybe first ignore my code. If you guys need to tackle this question, how will you write the code? — Ching Long LEE, Feb 12 '20 at 17:03

oldxavier · Answer 1 · 2020-02-12T16:58:10.950

0

You don't need the sum line and it works fine:

total = 0
count = 0
while True:
    n = input('Enter integers')
    if n.isdigit():
        print(n)
    else:
        break
    total += n
    count += 1
print(total)

edited Feb 12 '20 at 16:58

answered Feb 12 '20 at 16:52

oldxavier

66
6

== True not required. – Kanishk Tanwar Feb 12 '20 at 16:53
Good one, simplified it. – oldxavier Feb 12 '20 at 16:55
Thanks @Xavier! But I still couldn't get the summation going.. When I input 3,4,5, supposed I wanna receive 12 as the output. Not sure where exactly goes wrong. It could just run the integers I type – Ching Long LEE Feb 12 '20 at 16:55
it would be nice to explain to the op why their code is failing in the first place (which probably has to do with overwriting the built-in `sum`) – njzk2 Feb 12 '20 at 16:56
@ChingLongLEE you have indentation error, while true and then only input statement is working rest of your code is not accessible by python – Kanishk Tanwar Feb 12 '20 at 16:57
@njzk2 I don't think the code ever reached matching the built-in sum - sum(total) would always fail in the original code with TypeError - int object is not iterable. But I could be wrong. OP, if you stop your session, start a new one and run this code, it should definitely work and output 12 for 3-4-5. – oldxavier Feb 12 '20 at 17:05
@oldxavier good point, I assumed sum would accept a single value, but it doesn't, and it does throw a TypeError – njzk2 Feb 12 '20 at 17:09

score 0 · Answer 2 · answered Feb 12 '20 at 16:57

0

total = 0
count = 0
while True:
    print('Enter integers')
    n = input ()
    if (n.isdigit() == True):
        print (n)
        n = int(n)    
        total = total + n
        count = count + 1
    else:
        print('The total is ' + str(total))
        print('You put ' + str(count) + ' numbers')
        break

answered Feb 12 '20 at 16:57

Gutemberg Schiessl

61
3

Thanks @Gutemberg But still not sure why the summation still couldn't be achieved LOL again, I am expecting a 7 when I input 3 & 4 – Ching Long LEE Feb 12 '20 at 17:04

score 0 · Answer 3 · answered Feb 12 '20 at 19:09

By delegating the input process to an iterative function you will be able to use the sum() function directly to obtain the total:

def inputIntegers():
    while True:
        result = input("Enter integers: ")
        if not result.isdigit(): break
        yield int(result)

print("total:",sum(inputIntegers()))


Enter integers: 3
Enter integers: 25
Enter integers: 6
Enter integers: 4
Enter integers: 
total: 38

Python - Using if statement, + while condition | Print integers, break when having digits

3 Answers3