How can I convert the string [1,2,3,4,5] into an integer array?

Question

def array = [1,2,3,4,5]
def b = int[array.length]
for(int i = 0; i < b.length; i++){
    b[i] = Integer.parseInt(array[i])
}

Should I use Integer.parseInt, Integer.valueOf or other methods?

Should I include a for loop?

Does this answer your question? [Integer.valueOf() vs. Integer.parseInt()](https://stackoverflow.com/questions/7355024/integer-valueof-vs-integer-parseint) — Nexevis, Feb 13 '20 at 13:44
I'm not sure how the code you posted has anything to do with the title. — Federico klez Culloca, Feb 13 '20 at 13:45
I obtain a variable which result is the string 1,2,3,4,5 but I need it to be an integer array — Julies GQ, Feb 13 '20 at 13:55
"I obtain a variable which result is the string 1,2,3,4,5 but I need it to be an integer array" - That is very different than the code sample you included in the question. — Jeff Scott Brown, Feb 13 '20 at 17:45
It feels like at least once a day, someone asks about how to parse "accidental toString" back into some datastructure. While your question might be totally valid, be double sure, that you don't have to bother with this just because someone did the .toString() or a cast or could not decide for a proper format to transport structured data. — cfrick, Feb 14 '20 at 10:30

score 2 · Accepted Answer · answered Feb 13 '20 at 14:39

Instead of this:

def array = [1,2,3,4,5]
def b = int[array.length]
for(int i = 0; i < b.length; i++){
    b[i] = Integer.parseInt(array[i])
}

You could do this:

def array = [1,2,3,4,5]
def b = new int[array.size()]
for(int i = 0; i < b.length; i++){
    b[i] = i
}

You could also do this:

def array = [1,2,3,4,5]
def b = array.toArray(Integer[])

score 0 · Answer 2 · answered Feb 13 '20 at 14:48

0

Pattern.compile("\\d+")
    .matcher(s)
    .results()
    .map(MatchResult::group)
    .map(Integer::parseInt)
    .collect(Collectors.toList());

answered Feb 13 '20 at 14:48

kaya3

score 0 · Answer 3 · answered Feb 14 '20 at 10:27

0

Another option: take all numbers from the string as list and then cast them

"1, 2, 3".findAll(/\d+/) as Integer[]

answered Feb 14 '20 at 10:27

cfrick

3 Answers3