How to pass a class level generic to a method

Question

I have a class which accepts a generic parameter

class MyClass<D> {

  public void myMethod() {

   }

}

Now I have an external API method with the following signature?

public static <T> T apiMethod(String str, java.lang.Class<T> classOfT) {
}

I want something like the below, but I'm getting compilation error.

class MyClass<D> {

      public void myMethod(String str) {
            ApiClass.apiMethod(str,D); 

       }

 }

Any idea of how can I achieve that?

score 3 · Accepted Answer · answered Mar 18 '20 at 12:46

3

You can't do that. The best you can do is defer the responsibility to the caller, making them pass the class to the constructor.

class MyClass<D> {

   private Class<D> clazz;

   MyClass(Class<D> clazz) { 
       this.clazz = clazz;
   }

   public void myMethod() {
       ApiClass.apiMethod(str, clazz); 
   }
}

answered Mar 18 '20 at 12:46

Michael

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Awesome that's what I wanted, many thanks. – user1220373 Mar 18 '20 at 12:49
The linked duplicates already contain this answer, so you may aswell delete it again – Lino Mar 18 '20 at 12:49

How to pass a class level generic to a method

1 Answers1