Explain about java continue & break the following code briefly

Question

Explain briefly the function of the code below. About continue & break operations. I can't understand properly label1, label2.....Please describe code functions (The label is basically used in nested loops But note that they are used here to understand the labelling process)

class example {
    public static void main(String args[]) {
        int i = 0;
        int j = 0;
        label1: while (i++ < 5) {
            label2: for (;;) {
                label3: do {
                    System.out.print(i + " " + j + " ");
                    switch (i + j++) {
                    case 0:
                        continue label3;
                    case 1:
                        continue label2;
                    case 2:
                        continue label1;
                    case 3:
                        break;
                    case 4:
                        break label3;
                    case 5:
                        break label2;
                    case 6:
                        break label1;
                    default:
                        break label1;
                    }
                } while (++j < 5);
            }
        }
    }
}

you're using labels, having and increment in while condition , has noting in the for loop arguments , and having four nested loops , all of them are very bad programming practices don't do that, this program is not at all readable and in the first glance it doesn't seem to do anything, and if you just want to understand , label, break , continue just google it — Abhinav Chauhan, Mar 22 '20 at 04:21

Arvind Kumar Avinash · Accepted Answer · 2020-03-22T07:04:54.497

The following line first checks if 0 < 5 and then increases the value of i to 1:

while (i++ < 5)

Thus the following statement prints 1 0 as the value of i is now 1 and that of j is 0:

System.out.print(i + " " + j + " ");

As a result of the two above mentioned processings, the following line is evaluated as switch (1 + 0) and then the value of j is increased to 1:

switch (i + j++)

As a result of the above mentioned processing, case (1) becomes true and therefore the control goes to label2 and again falls back to the following statement which prints 1 1:

System.out.print(i + " " + j + " ");

Now, the following line is evaluated as switch (1 + 1) and then the value of j is increased to 2:

switch (i + j++)

As a result of the above-mentioned processing, case (2) becomes true and therefore the control goes to label1 from where it falls to the following line which first checks if 1 < 5 and then increases the value of i to 2:

while (i++ < 5)

Then it goes to the following statement which prints 2 2 as the value of i is now 2 and that of j is 2:

System.out.print(i + " " + j + " ");

And so on...

I hope, it is clear to you. Apart from this, I also recommend you follow Java naming convention e.g. class example should be class Example as per the naming convention.

Feel free to comment in case of any doubt/issue.

ok sir thank you very much – Shashini Prabodha Mar 22 '20 at 11:23 — Shashini Prabodha, Mar 22 '20 at 11:23

score 0 · Answer 2 · 2020-03-22T10:16:19.013

0

Break in Java means that it will exit the loop. In your case while(++j<5)

Continue skips the loop for one time, that means the loop will start from top and nothing below continue will execute.

If this help you please vote me up. I’am here new and want to have some basic reputation. Thanks!

edited Mar 22 '20 at 10:16

answered Mar 22 '20 at 06:19

Explain about java continue & break the following code briefly

2 Answers2