Why can't my float variable store numbers after the decimal point?

Question

#include <stdio.h>
main()
{
    int c=2,n=5;
    float percent;
    percent=(c/n)*100;
    printf("%.3f\n",percent);
}

what's wrong in this code please..?

so many duplicates: [Division result is always zero](https://stackoverflow.com/q/2345902/995714), [Integer division always zero](https://stackoverflow.com/q/9455271/995714), [calculation in C program always results in 0 whenever using division](https://stackoverflow.com/q/7720078/995714)... — phuclv, Mar 26 '20 at 05:34

srilakshmikanthanp · Accepted Answer · 2020-03-26T05:12:51.923

0

       percent=(c/n)*100;

       2/5    ---> 0 because it is integer division 
       0*100  ---> 0

It is an integer division, So you can change this to

       percent=((float)c/n)*100;

       2/5     ----> 0.4
       0.4*100 ----> 40.0

edited Mar 26 '20 at 05:12

answered Mar 26 '20 at 05:04

srilakshmikanthanp

2,231
1
8
25

score 0 · Answer 2 · answered Mar 26 '20 at 05:04

You are doing integer division. It always truncates the value. Make sure you cast either one first then it will use floating point division.

#include <stdio.h>
int main()
{
    int c=2,n=5;
    float percent;
    percent=((float)c/n)*100;
    printf("%.3f\n",percent);
}

score 0 · Answer 3 · answered Mar 26 '20 at 05:09

0

Division operation between integers yield another integer. Since c, n & 100 are integers you get an integer as a result with .0 since the type is declared as float. The other answers here should produce your desired answer.

answered Mar 26 '20 at 05:09

Kamruzzaman Tauhid

167
16

Why can't my float variable store numbers after the decimal point?

3 Answers3