How to add item to formData.serializearray()?

Question

I want to add another item to formData.serializeArray() and send formData with ajax to laravel controller. Here is what I have tried:

    var formData = $('#form').serializeArray();

formData.push({"name":"inputValue", "value": '1' });

$.ajax({

   url: 'url',

   type:"POST",

   data:  formData,

   dataType : 'json',

   cache: false,

   success: function (data) {

   }
 })

In jquery, data pushed correctly. but, it doesn't send pushed data with ajax . it just send form data without new item.

Why it doesn't send pushed data with ajax?

What do you see if you `console.log(formData)` after `formData.push`? Ideally this should work without issues — Anurag Srivastava, Mar 28 '20 at 07:42
It shows new item in console.log(formData). but, it doesn't send it with ajax. — Haniye Shadman, Mar 28 '20 at 07:45
And about that question, No I pushed data but it doesn't send data to controller. — Haniye Shadman, Mar 28 '20 at 07:48
Post your laravel code, the part where you parse the request — Anurag Srivastava, Mar 28 '20 at 07:49

Sarvil Ajwaliya · Answer 1 · 2020-03-28T07:41:20.600

0

Please try this:

formData.push({"name":"inputValue", "value": '1' });

This should work can you try once again by console.log(formData);

edited Mar 28 '20 at 07:41

answered Mar 28 '20 at 07:35

Sarvil Ajwaliya

233
1
8

`.push` must work correctly, and if it doesn't, then this won't too – Anurag Srivastava Mar 28 '20 at 07:43
Thanks, but it didn't work. – Haniye Shadman Mar 28 '20 at 07:55

How to add item to formData.serializearray()?

1 Answers1