Javascript: function is not a function

Question

Below I have the simplest code. In my name function its all good, it works but in the User_age function I get the following error:

User_age is not a function.

What am I doing wrong?

User_age();

function User_age()
{
    var age = promt("what is your age");
    var printAge = "your age is" + age;
    console.log(printAge);
}

name();

function name(){

    var username = prompt("what is your name");
    var greed = "hello" + username;
    console.log(greed);
}

Worked, perfectly fine for me. https://jsbin.com/qasovepeze/edit?js,console,output — Yash Vekaria, Apr 01 '20 at 12:08
Have you tried to have the parentheses on the same line as the function? — Gh05d, Apr 01 '20 at 12:10
[Don't use the name `name` for a global function](https://stackoverflow.com/questions/10523701/using-the-variable-name-doesnt-work-with-a-js-object) — Bergi, Apr 01 '20 at 12:13
(ok, sorry, it shouldn't be closed as a duplicate, I missed that the error is "*User_age is not a function.*") — Bergi, Apr 01 '20 at 12:14

score 1 · Accepted Answer · answered Apr 01 '20 at 12:10

1

you have a small issue in your first function you are typing promt not prompt

 User_age();

function User_age()
{
var age = prompt("what is your age");
var printAge = "your age is" + age;
console.log(printAge);
}

name();

function name(){

var username = prompt("what is your name");
var greed = "hello" + username;
console.log(greed);
}

answered Apr 01 '20 at 12:10

Wassim Ben Hssen

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check my answer for not posting others answers – Wassim Ben Hssen Apr 01 '20 at 12:16

Javascript: function is not a function

1 Answers1