How to overload multiple subscript of array index operator?

Question

Let's say I have a class, let it be foo. It contains object someclass obj[10][10].

Now I want to refer to bar, which is an object of type foo, in such a way that bar[7] is equivalent to bar.obj[7] and returns an object of type someclass*. It's rather simple.

But I also want to refer to bar in such a way that bar[7][3] is equivalent to bar.obj[7][3] and returns an object of type someclass. It's not that simple right now...

How to do it?

Maybe this will help: [Operator\[\]\[\] overload](https://stackoverflow.com/q/6969881/10871073) — Adrian Mole, Apr 08 '20 at 14:33
If you want the first one to return a pointer, the second dimension is already done. — chris, Apr 08 '20 at 14:36
it can be done, but the much simpler is to use `operator()(size_t,size_t)` instead — 463035818_is_not_an_ai, Apr 08 '20 at 14:38

eerorika · Accepted Answer · 2020-04-08T15:15:24.387

in such a way that bar[7] is equivalent to bar.obj[7] and returns an object of type someclass*.

But if it returns someclass*, then it wouldn't be equivalent to bar.obj[7]. It would need to return someclass(&)[10] in order to be equivalent.

Note that you may want to have a const overload as well.

But I also want to refer to bar in such a way that bar[7][3]

As long as you overload the subscript operator as described, you can do this - it works both with your pointer suggestion, and my reference suggestion.

How to overload multiple subscript of array index operator?

1 Answers1