python: format float string with maximum number of decimals

Question

what I need is similar to %.2f but so that any 0 or . endings are deleted.
An example follows, on the left are the float numbers and on the right the desired formatting.

4525.0014436  ->   '4525'
4525.0091     ->   '4525.01'
4525.1036     ->   '4525.1'
4525.163465   ->   '4525.16'
4525.998      ->   '4526'

Is there a way to get this formatted in python? Or is it necessary to do it algorithmically?

The second example - why 4525.1 rather than 4525.09 ? – Błotosmętek Apr 12 '20 at 16:39 — Błotosmętek, Apr 12 '20 at 16:39

score 0 · Answer 1 · answered Apr 12 '20 at 16:54

0

found: just use rstrip('0.') after formatting with %.2f

for example:

>>> ("%10.2f" % 4567.001).rstrip('0.')
'   4567'
>>> ("%10.2f" % 4567.009).rstrip('0.')
'   4567.01'
>>> ("%10.2f" % 4567.1004).rstrip('0.')
'   4567.1'

answered Apr 12 '20 at 16:54

mastupristi

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This does not work as expected for `0` as it returns an empty string. Maybe make a special condition for `0` like: `'0' if f==0. else ('%10.2f' % f).rstrip('0.')`. Otherwise nice solution. – Scindix Jul 04 '22 at 20:04

python: format float string with maximum number of decimals

1 Answers1