Custom Program - IndexOutOfBoundsException

Question

`this has been bugging me .giving me error.....can anyone tell me how to solve that: exception in thread "main" StringIndexOutOfBoundsException: String index out of range: 8'


   public class Solution {
   public static boolean checkit(String input){
       int i,j;
       boolean s=false;
       for(i=0;i<=input.length()-3;i++){
           for(j=i+2;j<=input.length()-1;j++)
           {
               if(input.charAt(i)==input.charAt(j+1) && input.charAt(i+1)==input.charAt(j))
                   s=true;

           }
       }
     return s;  
   }
   public static void main(String [] args){

       System.out.print(checkit("ABcBAxxs"));

}
}

on which line? it means you are trying to get the char at index 8, while the String has (max) 8 characters — Stultuske, Apr 16 '20 at 07:27

bruno · Accepted Answer · 2020-04-16T07:33:43.927

0

having

      for(j=i+2;j<=input.length()-1;j++)
      {
          if(input.charAt(i)==input.charAt(j+1) && input.charAt(i+1)==input.charAt(j))

when j values input.length()-1 then input.charAt(j+1) access at input.length() so out of your String

Out of that, when s become true it is useless to continue to loop because s cannot become false back. You can remove your variable s, replace s=true; by return true; and return s; by return false;

edited Apr 16 '20 at 07:33

answered Apr 16 '20 at 07:28

bruno

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ok i get it now..... about your comment actually it was just a code for checking occurrence of BA for AB if present return true...its solved now.....thnks – The_Eternal_Wisp Apr 16 '20 at 07:37

Custom Program - IndexOutOfBoundsException

1 Answers1