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I have below function inside an async function.

await saveStock(stock).then((res) => {
 addDrugToStock(stockDrug)
  addSupplierToStock(stockSupplier)

});

When I run this it always saveStock function gives appropriate results. but the other two functions are not executing properly. Sometimes addDrugToStock is working. In other times adSupplierToStock is working. How can I run both addDrugToStock and addSupplierToStock at a same time.

awpathum
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    `How can I **run** both... at a same time`. You cannot **run** but you can get the values at the same time – Tân Apr 17 '20 at 19:21
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    Use Promise.all for parallel function call https://stackoverflow.com/questions/35612428/call-async-await-functions-in-parallel –  Apr 17 '20 at 19:32

2 Answers2

1

If you want to execute both Promise objects and wait for both of them, then you need to use Promise.all: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/all

Danil Sabirov
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When using async/await operators you don't have to implement the .then() or .catch() handlers, just write code the synchronous way. Otherwise, you can use Promise.all to handle multiple independent Promises. 

try {
   // Equal to .then() in regular Promises

   const response = await saveStock(stock);

   addDrugToStock(stockDrug);
   addSupplierToStock(stockSupplier);
} catch (e) {
   // Equal to .catch() in regular Promises
}