'float' object cannot be interpreted as an integer in python

Question

I search some method that said using //operator, but I didn't understand how to use in my program

def trapezoid(x, a, b, c, d):
    if x <= a:
        return 0
    if a < x <= b:
        return (x - a)/(b - a)
    if b < x <= c:
        return 1
    if c < x <= d:
        return (d - x)/(d - c)
    if d < x:
        return 0 
for i in range(-100, 100, 0.01):
    small_y = trapezoid(i, -2.46, -1.46, 1.46, 2.46)

I tried to use i/0.01 or i//0.01 but show same error, and I don't want to change integer from float, I just want to calculate -100, -99.99, -99.98....

Bad option. If you're going to use NumPy, use `numpy.linspace`. `arange` with floating point inputs has major rounding error issues. — user2357112, Apr 18 '20 at 22:03

score 3 · Accepted Answer · answered Apr 18 '20 at 09:06

3

for i in range(-10000, 10000, 1):
    your_float = i*.01

answered Apr 18 '20 at 09:06

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'float' object cannot be interpreted as an integer in python

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