Python Var in def

Question

I made a input inside of a def function but need to use it in an if statement outside of the def function But it says the input is not defined

def mainmenu()
       Pick = input("input 1 for deposit, and so on")

If pick == "1":
   Deposit()

Variable is only defined in the scope method, you may return it — azro, Apr 25 '20 at 21:08
`Pick " input(` is not valid syntax. Did you mean `pick = input`? — Cory Nezin, Apr 25 '20 at 21:08
Does this answer your question? [Use of "global" keyword in Python](https://stackoverflow.com/questions/4693120/use-of-global-keyword-in-python) — michaeldel, Apr 25 '20 at 21:23

score 0 · Answer 1 · answered Apr 25 '20 at 21:11

0

It's hard to know what you're trying to do, but based on your example, you can use:

def pick():
   return input("input 1 for deposit, and so on")

if pick() == "1":
   # Deposit()
   print("execute Deposit()")

Demo

answered Apr 25 '20 at 21:11

Pedro Lobito

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Beny Gj · Answer 2 · 2020-04-25T21:20:24.867

0

you can do this is better approach instead to use if statement

menu_data = { '1' : func1, '2': func2} # etc...


def pick():
    user_input = input("input 1 for deposit, and so on")
    try:
      menu_data[user_input]() # call the method according to the input
    except KeyError as err:
        print('invalid key try again')
        pick()

edited Apr 25 '20 at 21:20

answered Apr 25 '20 at 21:19

Beny Gj

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4
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you don't need to check the input, the try catch handle it and you can call your function again to ask the user to enter again a valid input – Beny Gj Apr 25 '20 at 21:20
Python encourages the use of exceptions, which you handle – Beny Gj Apr 25 '20 at 21:23
you can see here https://stackoverflow.com/questions/7604636/better-to-try-something-and-catch-the-exception-or-test-if-its-possible-first – Beny Gj Apr 25 '20 at 21:24
delete all comments, forget this whole thing – new Q Open Wid Apr 25 '20 at 21:37

score 0 · Accepted Answer · answered Apr 25 '20 at 21:20

Because the variable pick is only a local variable (one inside a function) and not a global variable (one that can be accessed everywhere), you have to return it to access the variable globally.

def pick():
  pick = input("input 1 for deposit, and so on")
  return pick

if pick() == "1":
  Deposit()
  # and so on...

Thus, you can access it by running the function. Then check if it is equal to one.

Python Var in def

3 Answers3