Issue with output from an if...else function in python

Question

I am trying to write a function in Python that would return a colour value after evaluating to a user value. This what I have tried, however, I am not get what I expect, a single colour. I am getting a list of colours. I am new to programming.

uservalue = 100000

def colour(m,i):
    if uservalue > (m + i):
        clrs == "red"                  
    elif uservalue < (m - i):
        clrs == "blue"              
    else:
        clrs == "white"         
    return clrs

to test I use this input:

colour(20000, 3000)

output:

['red', 'red', 'red', 'white', 'white', 'white', 'white']

I was looking for one colour returned after evaluation.

... and `clrs` was defined before somewhere else in your code with the value `['red', 'red', 'red', 'white', 'white', 'white', 'white']` — Thierry Lathuille, Apr 26 '20 at 16:34

score 0 · Answer 1 · answered Apr 26 '20 at 16:35

uservalue = 100000

def colour(m,i):
    if uservalue > (m + i):
        clrs = "red"                  
    elif uservalue < (m - i):
        clrs = "blue"              
    else:
        clrs = "white"         
    return clrs

print(colour(20000, 3000))

output will be: red

score 0 · Answer 2 · answered Apr 26 '20 at 17:05

0

you are almost there. replace == with =. == is referred when checking equality and = is referred when assigning a value to a variable. try below code.

uservalue = 100000

def colour(m,i):
    if uservalue > (m + i):
        clrs = "red"                  
    elif uservalue < (m - i):
        clrs = "blue"              
    else:
        clrs = "white"         
    return clrs

answered Apr 26 '20 at 17:05

lone_ranger

75
4

Thank you so much, that little error cost me hours and sleep. – Celtis Apr 26 '20 at 17:52
@Celtis you are welcome. If my answer make sense, please upvote – lone_ranger Apr 26 '20 at 20:27

Issue with output from an if...else function in python

2 Answers2