I have a code of line as:
Pattern pattern = Pattern.compile("^\\d{1,4}\\,(.*?),");
I want to understand what exactly is getting done in above regular expression,i.e.
"^\\d{1,4}\\,(.*?),"
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It will match strings that begin with 1-4 digits, followed by `,` followed by one optional character, followed by a `,`. You can use [regex101.com](https://regex101.com/r/VIGYhg/1) to explore and understand regular expressions. – stackprotector Apr 29 '20 at 05:59
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Does this answer your question? [Reference - What does this regex mean?](https://stackoverflow.com/questions/22937618/reference-what-does-this-regex-mean) – tripleee Apr 29 '20 at 07:45
1 Answers
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^\d{1,4},(.*?),
Explaination:
^\d{1,4}-- means must begin with between 1 to 4 digits (characters between 0 and 9)...\,-- means then there have,(.*?)-- means there will be any character 0 or more times but will happen 0 or 1 time...- , -- means there is one more
,
Look at this demo.. you will get better explaination here
Look at this answer to learn about regex.....
GolamMazid Sajib
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The question's broken formatting obscured the `*`; the expression is actually `(.*?)` – tripleee Apr 29 '20 at 07:47
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@tripleee updated. thanks. pls give more improvement for this point. i can not explain clearly – GolamMazid Sajib Apr 29 '20 at 07:49
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It's a non-greedy match; but probably simply delete this answer and refer to the duplicate instead. – tripleee Apr 29 '20 at 07:50