Is there a way in Python to uniformly add an element to a list no matter if it already exists?

Question

If I have, for example, a dictionary d and I want to add the value v - amongst possibly more of them in a list - to the key k, I usually do it this way:

if k in d:
    d [k].append (v)

else:
    d [k] = [v]

Is there a more elegant way, e.g. like

list_append (d [k],  v)

? The problem occurs for me mainly at dictionaries but a solution should not be restricted to them.

U13-Forward · Answer 1 · 2020-04-30T09:58:36.067

0

Use setdefault:

d.setdefault(k, []).append(v)

edited Apr 30 '20 at 09:58

answered Apr 30 '20 at 09:55

U13-Forward

69,221
14
89
114

I'm sorry, I edited the question because it was not made clear that there could be more elements in the value list. – Stephan Geue Apr 30 '20 at 09:57
@StephanGeue Strange, try it again, it worked for me – U13-Forward Apr 30 '20 at 09:59

Is there a way in Python to uniformly add an element to a list no matter if it already exists?

1 Answers1