Finding numbers within certain string in Python

Question

I'm starting to learn Python and just now getting into regular expressions. I want to figure out what is the best way to search a string to find a number (which can be different lengths) that is always directly following a certain substring.

For example:

string = """ this is a very long string with 495834 other numbers;
             if I had the ( 5439583409 );
             Keyword_indicator( 53029453 ); //
             energy to type more and more; ..."""

I want to be able to search the string for "Keyword_indicator" which only shows up here, then pull the number within the parenthesis, knowing the number isn't a set length.

output = "53029453"

Edit - The string has other numbers in it, and the number I'm looking for is always an integer.

Does this answer your question? [Get only numbers from string in python](https://stackoverflow.com/questions/28526367/get-only-numbers-from-string-in-python) — Aaron, May 22 '20 at 21:45

score 2 · Answer 1 · answered May 22 '20 at 21:49

2

import re
string = """ this is a very;
             long string if I had the;
             Keyword_indicator( 53029453 ); //
             energy to type more and more; ..."""
m = re.search('Keyword_indicator.*?(\d+)', string)
output = m.group(1)

answered May 22 '20 at 21:49

Błotosmętek

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Upvoted for providing a regex solution. – mechanical_meat May 22 '20 at 21:54
I think this is what i'm looking for thank you for the help. – Tanner Z May 22 '20 at 21:59
1

You may wish to tighten this a bit as it matches the digits in `Keyword_indicators are needed, call me at 53029453 )` – Cary Swoveland May 22 '20 at 23:51

score 1 · Answer 2 · answered May 22 '20 at 22:09

In your case you can use:

import re
string = """ this is a very long string with 495834 other numbers;
             if I had the ( 5439583409 );
             Keyword_indicator( 53029453 ); //
             energy to type more and more; ..."""

#This would also match 5439583409 from bla5439583409bla.
re.findall(r'\d+', string)
result will be:
['495834', '5439583409', '53029453']

#If you only want numbers delimited by word boundaries (space, period, comma), you can use \b :
re.findall(r'\b\d+\b', string)
result will be:
['495834', '5439583409', '53029453']

#list of numbers instead of a list of strings:
[int(s) for s in re.findall(r'\b\d+\b', string)]

Red · Answer 3 · 2020-05-22T23:20:05.957

0

Here's one way of doing it:

string = 'biu89'
numbers = ''
for l in string:
    try: numbers+=str(int(l))
    except: pass
print(numbers)

Output:

note: All numbers will be concatenate to one.

edited May 22 '20 at 23:20

answered May 22 '20 at 21:51

Red

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Brenden Price · Answer 4 · 2020-05-23T03:01:16.510

-1

Could could try something similar to the following:

>>> import re #import rejex
>>> just='Standard Price:20000' #provide a string
>>> re.search(r'\d+',just).group() #searches string for a digit values and groups
'20000' #result

So it would be something to the effect of:

string = """ this is a very;
             long string if I had the;
             Keyword_indicator( 53029453 ); //
             energy to type more and more; ...""" #OP provided string
print(re.search(r'\d+', string).group()) #search for digit values in OP provided string, group, and output the result.

edited May 23 '20 at 03:01

answered May 22 '20 at 21:48

Brenden Price

517
2
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The code isn't very clear. – 10 Rep May 22 '20 at 22:27

Finding numbers within certain string in Python

4 Answers4