error- IndentationError: unindent does not match any outer indentation level

Question

I am a beginner with the Python. I am trying to run the following code to replace some labels in .txt annotation files.

import os

for txt_in in os.listdir(r"uncorrected-YOLO_darknet"):
    with open(txt_in) as infile:
        for line in infile:
            word=line.split(" ")[0]
            if word="6":
                word.replace('6', '5')
            elif word="9":
                word.replace('9', '6')
            elif word="10":
                word.replace('10', '7')
            elif word="11":
                word.replace('11', '8')
            else:
                continue
            break

but I am getting the following error:

File "<tokenize>", line 7
    if word="6":
    ^
IndentationError: unindent does not match any outer indentation level

I tried to find the indentation error but it looked alright to me. Plz help. tnx!

You've got mixed tabs and spaces. Find your editor's "convert tabs to spaces" button and hit it, set your indentation to spaces, and check for this if it comes up again. — user2357112, May 24 '20 at 03:11

score 1 · Answer 1 · answered May 24 '20 at 03:14

You use wrong Syntex of If and elif condition
Try below code

        if word=="6":
            word.replace('6', '5')
        elif word=="9":
            word.replace('9', '6')
        elif word=="10":
            word.replace('10', '7')
        elif word=="11":
            word.replace('11', '8')
        else:
            continue
        break

score 1 · Accepted Answer · answered May 24 '20 at 03:34

if/elif takes a statement that returns a boolean value.

== is one such operator that checks for equality and returns true/false.

What you have in your code is =, which is an assignment operator and it does not check for equality.

Replace all the if/elif statements like this:

if word == "6":

error- IndentationError: unindent does not match any outer indentation level

2 Answers2