Reading txt file in java, program skipping the first line

Question

My program is skipping the first line of my .txt file. Here is where my code is supposed to read from the .txt file.

static int getPints(int[] pints) throws IOException {
    Scanner inputFile = new Scanner(new File("BloodInFile.txt"));
    int count = 0;
    while (inputFile.hasNext()) {
        pints[count] = inputFile.nextInt();
        count++;
    }
    return pints[count];
}

It should be reading 7 integers, but I only get 6 of them to be read. The rest of the code works, but I am not sure how to get it to read the first integer.

This is the rest of my code:

static int getPints(int[] pints) throws IOException {
    Scanner inputFile = new Scanner(new File("BloodInFile.txt"));
    int count = 0;
    while (inputFile.hasNext()) {
        pints[count] = inputFile.nextInt();
        count++;
    }
    inputFile.close();
    return pints[count];
}

static double getAverage(int pints[], int MAX_HOURS) {
    int counter;
    double totalPints = 1;
    double averagePints;
    for (counter = 1; counter < MAX_HOURS - 1; counter++) {
        System.out.println("pints:" + pints[counter]);
        totalPints = totalPints + pints[counter];
    }
    averagePints = totalPints / (MAX_HOURS - 2);
    System.out.println("Total pints: " + totalPints);
    return averagePints;
}

static double getHigh(int pints[], int MAX_HOURS) {
    int index = 1;
    double highest = pints[index];
    for (index = 1; index < MAX_HOURS - 1; index++) {
        if (pints[index] > highest) {
            highest = pints[index];
        }
    }
    return highest;
}

static double getLow(int pints[], int MAX_HOURS) {
    int index = 1;
    double lowest = pints[index];
    for (index = 1; index < MAX_HOURS - 1; index++) {
        if (pints[index] < lowest) {
            lowest = pints[index];
        }
    }
    return lowest;
}

With `pints[count]` you'll get only the last read element anyway. — Balastrong, May 29 '20 at 19:40
Nah, they'll get one after that, since `count++` is done after reading into index `count`. So next thing should be an `ArrayIndexOutOfBoundsException`, but I'm guessing the array size is prepared beforehand 'to be safe'. — pafau k., May 29 '20 at 19:43

score 0 · Answer 1 · answered May 29 '20 at 19:44

I did it once just like this, maybe that works for you too

public static List<String> get16TeamsFromTxt() throws IOException {
    Path currentRelativePath = Paths.get("");
    String s1 = currentRelativePath.toAbsolutePath().normalize().toString();

    Scanner s = new Scanner(new File(s1+"/16.txt"));
    ArrayList<String> list = new ArrayList<String>();
    while (s.hasNextLine()){
        list.add(s.nextLine());
    }
    s.close();

    return list;

}

This way you should get the list with all of your numbers. Mine is with string, but should work with int.

Reading txt file in java, program skipping the first line

1 Answers1