positive lookahead string matching to a symbol

Asked Jun 03 '20 at 22:08

Active Jun 03 '20 at 22:12

Viewed 23 times

I have a string like this test |firstresult |secondresult |thirdresult

I'd like the output to be a string with a new line for every | available

Expected Output:

test |firstresult |secondresult |thirdresult

I've tried using str.split but the delimeter is lost. I've also tried str.split(/(?=|)/) which doesn't seem to like the | symbol.

Thanks for your help in advance

asked Jun 03 '20 at 22:08

Leslie Alldridge

1

why do you think it doesn't "like" the symbol? Maybe it would work if it was escaped with a backslash? – Namaskar Jun 03 '20 at 22:10
2

To match a literal pipe, escape it. `str.split(/(?=\|)/)` or `str.split(/\s*(?=\|)/)` will work – Wiktor Stribiżew Jun 03 '20 at 22:10
thanks, escaping the | worked `str.split(/(?=[|])/)` – Leslie Alldridge Jun 03 '20 at 22:11
simply replace `(?=\|)` with newline. if its split has to be joined waste of time – Jun 03 '20 at 23:27

0 Answers0