Linux variable value not working when running from script

Question

This is MyScript.sh

I want to execute a script as a text inside my script, I have tried to do it like so:

bash -c "
    #!/bin/bash
    STR=6
    echo $STR
"

Prints empty line.

I tried replacing bash -c with sh -c or eval, all options acts the same, why is that and how can it be solved?

Use single quotes instead of double quotes... – Jetchisel Jun 28 '20 at 08:27 — Jetchisel, Jun 28 '20 at 08:27

score 1 · Accepted Answer · answered Jun 28 '20 at 08:29

1

Using single quotes to avoid interpretation in the current shell:

$ cat myscript.sh
bash -c 'STR=6; echo $STR' 
./myscript.sh
6

answered Jun 28 '20 at 08:29

pifor

1 Answers1