How to get the base url from the jsp request object? http://localhost:8080/SOMETHING/index.jsp, but I want the part till index.jsp, how is it possible in jsp?
            Asked
            
        
        
            Active
            
        
            Viewed 9.9k times
        
    32
            
            
        - 
                    there are many ways. Why exactly do you need it? – Bozho Jun 07 '11 at 20:20
- 
                    I have some requirement for which I need the url of the web container. So, I need a path till http://localhost:8080/my_web_container. – Maverick Jun 07 '11 at 20:22
- 
                    this is now "web container", but "context". And do you need it absolute, or relative (to the host) – Bozho Jun 07 '11 at 20:24
6 Answers
56
            So, you want the base URL? You can get it in a servlet as follows:
String url = request.getRequestURL().toString();
String baseURL = url.substring(0, url.length() - request.getRequestURI().length()) + request.getContextPath() + "/";
// ...
Or in a JSP, as <base>, with little help of JSTL:
<%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<%@taglib prefix="fn" uri="http://java.sun.com/jsp/jstl/functions" %>
<c:set var="req" value="${pageContext.request}" />
<c:set var="url">${req.requestURL}</c:set>
<c:set var="uri" value="${req.requestURI}" />
...
<head>
    <base href="${fn:substring(url, 0, fn:length(url) - fn:length(uri))}${req.contextPath}/" />
</head>
Note that this does not include the port number when it's already the default port number, such as 80. The java.net.URL doesn't take this into account.
See also:
- 
                    what is the reason that setting the `var` for the "url" follows different syntax than setting the `var` for "req" and "uri" ? – Marcus Junius Brutus Dec 24 '16 at 03:54
14
            
            
        new URL(request.getScheme(), 
        request.getServerName(), 
        request.getServerPort(), 
        request.getContextPath());
 
    
    
        Bozho
        
- 588,226
- 146
- 1,060
- 1,140
- 
                    1what you you mean "till"? It will generate what you want, I think. Try it. – Bozho Jun 07 '11 at 20:24
- 
                    2Note that this will even for default port numbers (http+80 and https+443) still include the port number in the final result. This is not always desireable, for sure not if the URL is to be used in some redirect URL or as `` URL. – BalusC Jun 07 '11 at 20:34 
0
            
            
        There is one major flaw in @BalusC accepted answer though. Substring should start from 0 and not 1. Instead of
<base href="${fn:replace(req.requestURL, fn:substring(uri, 1, fn:length(uri)), req.contextPath)}" />
it should be
<base href="${fn:replace(req.requestURL, fn:substring(uri, 0, fn:length(uri)), req.contextPath)}" />
With 1 you get double forward slash: http://localhost:8080//appcontext/
With 0 you get, http://localhost:21080/appcontext/
In my application, request.getSession(false) always returned null when it was ending in double slash!!!
 
    
    
        Boss Man
        
- 587
- 2
- 12
-3
            
            
        Instead of doing all of that, just do this:
request.getServerName().toString()
 
    
    
        Quinton Pike
        
- 3,823
- 8
- 31
- 37
 
     
     
     
    