Regex capture groups of N and the remainder?

Question

Supposing, I have a string ASDFZXCVQW, is it possible to capture this into groups of N, and then the remaining characters would be in the final group.

For example, if N were 4, then we could have: ASDF, ZXCV, and QW. Notice how the QW is everything that is left over.

I know how to capture the groups of N with .{N}, and then manually get the leftover through string indexing, but is it possible to do this in a single regular expression?

Maybe `/.{1,4}/g`. What language are you using? – Nick Parsons Jul 04 '20 at 08:06 — Nick Parsons, Jul 04 '20 at 08:06

score 0 · Accepted Answer · answered Jul 04 '20 at 08:17

0

var data = 'ASDFZXCVQW'

var result = data.match(/\D{1,4}/g)

console.log(result)

It will be helpful!

answered Jul 04 '20 at 08:17

Jay Parmar

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score 0 · Answer 2 · answered Jul 04 '20 at 08:19

That really depends on the language in use. In general, it will be a concatenation of 0 or more 4-character groups followed by 0-3 single characters. Here is a possible formal definition for alphanumeric string: ([a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9])*[a-zA-Z0-9]*. Different languages might express this differently and possibly in a more compact way.

Regex capture groups of N and the remainder?

2 Answers2