Invoke function within a function

Question

I am trying to grasp the concept of closure function in javascript. Below is a simple code.Need to pass an argument of "inside" to the innerFunction. how do i do it.

     function outerFunction(outerVariable){
         function innerFunction(innerVariable){
                  console.log("Outer Variable" +" = "+ outerVariable);
                  console.log("Inner Variable" +" = "+ innerVariable);
        }
        return innerFunction;
      };

     const newOutFunction = outerFunction("outside");

     newOutFunction();

since `outerFunction` returns the inner function (which you then store in `newOutFunction`), you can pass arguments into it using: `newOutFunction("inside")` — Nick Parsons, Jul 17 '20 at 07:03

score 0 · Answer 1 · answered Jul 17 '20 at 07:08

Do you mean this?

     function outerFunction(outerVariable){
     function innerFunction(innerVariable){
              console.log("Outer Variable" +" = "+ outerVariable);
              console.log("Inner Variable" +" = "+ innerVariable);
    }
    return innerFunction;
  };

 const newOutFunction = outerFunction("outside");
 let new_var = "inside"
 newOutFunction(new_var);

Invoke function within a function

1 Answers1