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Im trying to write a function takes the X Coordinate from an existing column and multiplies it by negative 1 if certain conditions are met. The function compiles fine, but I keep getting hit with the The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all(). error message once I apply it to the column of interest.

My function:

def xCoordFlip(xCoord):
  for xCoord in df['xCoord']:
    if df.loc[(df.period == 2) & (df.period == 4) & (df.name == 'A')]:
      return df['xCoord'] *-1
    if df.loc[(df.period == 1) & (df.period == 3) & (df.name == 'A')]:
      return df['xCoord']
    if df.loc[(df.period == 2) & (df.name == 'B')]:
      return df['xCoord'] *-1
    if df.loc[(df.period == 1) & (df.period == 3) & (df.name == 'B')]:
      return df['xCoord']

Basically I want to write a function that takes an X Coordinate and flips it if certain conditions are met. I'm guessing my understanding of Boolean conditions and their applications is way off, so any help would be most appreciated.

python_infant
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1 Answers1

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You should be using "and" instead of "&" right now you're using bitwise and instead of a boolean and

Actually it looks like I am wrong here.

Truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all()

This seems to answer your question well.

Pavel
  • 72
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