I have a pandas dataframe as follows:
0 False
1 False
2 False
3 False
4 True
...
1569 False
1570 False
I need to get the indices that are True, so [4] in this case or something. How do i do that?
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1`df.col[lambda x: x].index` – Psidom Jul 21 '20 at 15:57
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IIUC `df[df[col].eq(True)].index.tolist()` – Umar.H Jul 21 '20 at 15:58
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AttributeError: 'Series' object has no attribute 'col' – raaj Jul 21 '20 at 15:59
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sorry its a series object – raaj Jul 21 '20 at 16:00
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1For Series, `s[s].index` – Psidom Jul 21 '20 at 16:02
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@Psidom I don't think the addition of adding `.index` warrants its own question - can you close as a duplicate? – Umar.H Jul 21 '20 at 16:07
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`s[s].index` doesnt work. that just gives the index after the series has been modified. this will just give me 1, i want 4 – raaj Jul 21 '20 at 16:12
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I'm going to guess this is impossible, i just converted that pandas.series object into a numpy array and ran a np.where operation to get the indicies – raaj Jul 21 '20 at 16:13
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@raaj `s[s].index` should work. Check the linked duplicates plz. – Psidom Jul 21 '20 at 16:15