Getting error in a try, else statement. (python)

Question

I have this code:

with gui.Download:
if gui.is_running:  
    try: 
        dialog = str( QFileDialog.getExistingDirectory() )
    else:
        subprocess.call(['/bin/youtube-dl', gui.url])

and whenever I run it I get an error on the else block in the try, else statement. Any ideas?

Error:

      File "init.py", line 15
    else:
    ^
SyntaxError: invalid syntax

`else` is an optional clause in a `try`...`except`-statement, that is executed if no exception is raised. what you probably are looking for in your case is `except` — sim, Jul 23 '20 at 14:20
I want to run that code if the try statement succeeds, hence the else — reesericci, Jul 23 '20 at 14:22
yes, you would need a blank (`except: pass`) `except` (if that makes sense in your context). — sim, Jul 23 '20 at 14:27

score 0 · Answer 1 · answered Jul 23 '20 at 14:32

0

I just ended up using an if statement instead, works great!

if gui.is_running:
    dialog = str( QFileDialog.getExistingDirectory() )
    if dialog == '':
        pass
    else:
        subprocess.call(['/bin/youtube-dl', gui.url])

answered Jul 23 '20 at 14:32

reesericci

53
1
8

Now I understand your goal. Maybe `if dialog != '':` and then `subprocess.call(['/bin/youtube-dl', gui.url])` is cleaner. – Rorepio Jul 23 '20 at 14:39
`if dialog != '': subprocess.call(['/bin/youtube-dl', gui.url])` – Andreas is moving to Codidact Jul 24 '20 at 03:22

Getting error in a try, else statement. (python)

1 Answers1