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I am learning about malloc function & I see this difference but I cannot understand it

What is the difference between

ptr = (*int) malloc(sizeof(int)*N)

and

ptr = malloc(sizeof(int)*N)
Jonathan Leffler
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Takeshi Camilo Ramirez
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    `ptr = (*int) malloc(sizeof(int)*N)` is invalid syntax (specifically `*int` part is) and emit compile error while `ptr= malloc(sizeof(int)*N)` doesn't. – MikeCAT Jul 23 '20 at 17:04
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    Casting the return of `malloc` has been discussed [once or twice before](https://stackoverflow.com/questions/605845/do-i-cast-the-result-of-malloc). – ryyker Jul 23 '20 at 17:05
  • changing the tags makes answer almost off topic – 0___________ Jul 23 '20 at 17:12

1 Answers1

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In C cast of the malloc is considered the bad practice.

C++ is more type strict and you need to cast if you want to assign pointer with pointer of other type. But I would rather avoid direct use of the malloc (and generally pointers) in the C++ program.

In both I would rather use object in the sizeof operator

ptr = malloc(sizeof(*ptr)*N);

0___________
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