How to find the item of a list in a directory?

Question

• I need to parse .docx document and find out that if .wav files mentioned in the document are available in a sound directory(if sound directory exists with some .wav file) or not.
• I am able to parse the document and able to store the .wav files name in a list, but I have no idea how to search if the list items are available in the sound directory or not.
• Also, I cannot provide the full path of sound directory.
• My directory structure is like "E:\Package\somefolder\sound"
• My code is storing the list is mentioned below.

import os
import docx2txt
import re
    
parent_dir = "E:\PackageTesting" # Your directory here

def get_all_files(dir_name):
    file_list = os.listdir(dir_name)
    all_files = list()

    # Iterate over all the entries
    for entry in file_list:
        # Create full path
        full_path = os.path.join(dir_name, entry)
        # If entry is a directory then get the list of files in this directory
        if os.path.isdir(full_path):
            all_files = all_files + get_all_files(full_path)
        else:
            all_files.append(full_path)
    
    return all_files

all_files_in_dirs = get_all_files(parent_dir)

for file in all_files_in_dirs:
    if "Sound_Doc" in os.path.basename(file) and os.path.splitext(file)[1] == ".docx":
        print(format(file))
        MY_TEXT = docx2txt.process(format(file))
        wav = re.findall(r'[\w\.-]+w+a+[\w\.-]+', MY_TEXT)
        print(wav)

Answer 1

You can have a list of all files in a directory and browse it with those lines:

import os

for filename in os.listdir(directory):
    with open (directory+'/'+filename) as f:
        #your code here

Answer 2

Have a look at this post, it contains information on how to recursively look for files in a directory. So you could look for each of the wav files like this:

import os

def find_file(root_dir, filename):
    for root, dirs, files in os.walk(root_dir):
        for file in files:
            if file == filename:
                 return True # return true if file was found
    print("Not found: " + filename) # print full path
    return False # return false if file was not found

for wav_file in wav_file_list:
    find_file(parent_dir, wav_file)

If you have a lot of files and directories, you might want to put all wav files into a set to speed up the lookup, otherwise you script might take a long time to run.

Create the set like this:

import os

def find_all_wav_files(root_dir):
    wav_files = set()
    for root, dirs, files in os.walk(root_dir):
        for file in files:
            if file.endswith(".wav"):
                 wav_files.add(os.path.join(root, file))
    return wav_files

You can then check if the wav files exist like this:

wav = parse_your_docx(docx_file)
wav_files = find_all_wav_files("your/sound/directory")

for w in wav:
    if w in wav_files:
        print(w + " exists!")
    else:
        print(w + " does not exist!")

The function find_all_wav_files() will return a set of all wav files in the directory you specify as first argument. You can then search it like a list as shown in the second code snippet.

Answer 3

you can use glob module to list the file and directory in the directory.

The glob module finds all the pathnames matching a specified pattern according to the rules used by the Unix shell, although results are returned in arbitrary order.

**syntax:**
 glob.glob(pathname, *, recursive=False)

Return a possibly-empty list of path names that match pathname, which must be a string containing a path specification. pathname can be either absolute (like /usr/src/Python-1.5/Makefile) or relative (like ../../Tools//.gif), and can contain shell-style wildcards. Broken symlinks are included in the results (as in the shell). Whether or not the results are sorted depends on the file system.

Note:use * to list everything similarly '.wav' and '.docx' for wav file and document respectively.

ex: glob.glob('E:\Package\somefolder\sound\'+'*.wav')