Find String in Array in Java

Question

Why do I get nothing when run the code?

Scanner sc = new Scanner(System.in);

    String fname = sc.nextLine();
    String[] farray = new String[]{"Chen", "Chang"};

    if(Arrays.asList(farray).contains(farray)){
        System.out.println("Exits");
    }

Is there a logical error I made?

farray doesn't has itself in its elements, so yes it's a logical error. — Arpit Bhadauria, Aug 01 '20 at 05:07
Try looking for `"Chen"` or `"Chang"` in the array, you will get `"Exits"` printed. — Arpit Bhadauria, Aug 01 '20 at 05:08
I think that you used `contains(farray)` instead `contains(fname)` which is the value you get from the scanner — Omri Attiya, Aug 01 '20 at 05:08
Does this answer your question? [How do I determine whether an array contains a particular value in Java?](https://stackoverflow.com/questions/1128723/how-do-i-determine-whether-an-array-contains-a-particular-value-in-java) — Thirumal, Aug 01 '20 at 05:50

Omri Attiya · Accepted Answer · 2020-08-01T05:42:38.047

2

You have a typo, you used farray instead fname

if(Arrays.asList(farray).contains(fname)) {
    System.out.println("Exits");
}

edited Aug 01 '20 at 05:42

answered Aug 01 '20 at 05:18

Omri Attiya

3,917
3
19
35

score 1 · Answer 2 · answered Aug 01 '20 at 05:12

This expression will return false as it farray does not have itself in this. It is that simple as that. So nothing got printed.

Arrays.asList(farray).contains(farray) // false

You can look for element in array. like

Arrays.asList(farray).contains("Chang") // return true

Find String in Array in Java

2 Answers2