Return only protocol and domain from full URI string

Question

Given a full URI string I want to return only the protocol and domain name. For example:

sometodo("http://127.0.0.1:8000/hello/some/word1212/") 
// return: http://127.0.0.1 
    
sometodo("http://127.0.0.1:8000/hello/some/valorant_operator/") 
// return: http://127.0.0.1

How can I remove the third / and the following information from the string?

Please show us what you have tried. Also you should be able to find many answers to this if you just search a bit, since this has been answered many times before. — Carsten Løvbo Andersen, Aug 04 '20 at 09:01
jQuery is a framework primarily for amending the DOM. To manipulate strings you just need plain old JS — Rory McCrossan, Aug 04 '20 at 09:02
Does this answer your question? [Get protocol, domain, and port from URL](https://stackoverflow.com/questions/6941533/get-protocol-domain-and-port-from-url) — n9iels, Aug 04 '20 at 09:05

Dropout · Answer 1 · 2020-08-07T11:42:36.583

2

If it's going to be URLs then work with it as you would with an URL. No need to parse/regex/substring, just make an URL object and access its values.

https://developer.mozilla.org/en-US/docs/Web/API/URL

const url = new URL("http://127.0.0.1:8000/hello/some/word1212/");
let result = `${url.protocol}//${url.host}`;

edited Aug 07 '20 at 11:42

answered Aug 04 '20 at 09:09

Dropout

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Andrew Arthur · Accepted Answer · 2020-08-04T09:32:19.650

0

    sometodo("http://127.0.0.1:8000/hello/some/word1212/");
    sometodo("http://127.0.0.1:8000/hello/some/valorant_operator/");
    
    function sometodo(str) {        
        var output = str.match(/^(?:[^\/]*\/){3}/)[0];
        console.log(output);
        return output;
    }

edited Aug 04 '20 at 09:32

answered Aug 04 '20 at 09:26

Andrew Arthur

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Return only protocol and domain from full URI string

2 Answers2