Edit: this question is based on two mistakes: not originally yincluding self in methods and assuming unbounded methods would not exhibit polymorphism, but they do. I voted to close it.
I can take a method as a function-valued object in Python:
class A:
def foo(self):
return "Hi, I'm A.foo"
f = A.foo
a = A()
print(f(a))
produces Hi, I'm A.foo.
So far so good. However, f won't work for sub-classes:
class B(A):
def foo(self):
return "Hi, I'm B.foo"
f = A.foo
b = B()
f(b)
still produces Hi, I'm A.foo, whereas b.foo() produces Hi, I'm B.foo. In other words, polymorphism does not apply.
Question: is there a way to get a function-valued object in f so that f(x) == x.foo() whenever isinstance(x, A)?
In other words, how do I complete the snippet below for things to work?
class A:
def foo(self):
return "Hi, I'm A.foo"
class B(A):
def foo(self):
return "Hi, I'm B.foo"
f = <WHAT DO I PUT HERE?>
a = A()
b = B()
assert f(a) == a.foo()
assert f(b) == b.foo()