Why can I not assign publicip.get() to a variable?

Question

Update

If I do print(publicip.get()) then I get the correct ip addressed printed.

If I do myip = publicip.get() and then do print(myip), then the value None gets printed

Original Question

When I ran the site on localhost, the value of myip would be 127.0.0.1. But publicip.get() would give me my public IP address. Unfortunately if myip = "127.0.0.1": and if myip = 127.0.0.1: give me syntax errors. What is the correct way of checking the value in the variable myip.

     myip, is_routable = get_client_ip(request)
     if myip = "127.0.0.1":
        myip = publicip.get()

     print("myip")
     print(myip)

score 2 · Answer 1 · answered Aug 10 '20 at 16:34

2

= is an assignment operator, while equality can be checked with ==.

answered Aug 10 '20 at 16:34

Heap Underflow

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1
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Thank you. Do you know why ip = publicip.get() would not be working? print(publicip.get()) prints out my correct IP address. But when I do ip = publicip.get(), then ip equals None. – Ross Symonds Aug 10 '20 at 16:41
What kind of object is `publicip`? – Heap Underflow Aug 10 '20 at 17:13
How would I determine what sort of object it is? – Ross Symonds Aug 10 '20 at 17:15
Okay, seems like publicip is a package. Its function `get()` seems to just print the IP address, not return it. It would be difficult to grab it out there. – Heap Underflow Aug 10 '20 at 17:22
That is frustrating. Thank you for having a look. – Ross Symonds Aug 10 '20 at 17:23
But it might be even unnecessary to get the own "public" IP address. Most network software does not need this information to work. Therefore it would be good to know what you want to do. – Heap Underflow Aug 10 '20 at 17:26
Let us [continue this discussion in chat](https://chat.stackoverflow.com/rooms/219565/discussion-between-ross-symonds-and-heap-underflow). – Ross Symonds Aug 10 '20 at 19:16

Why can I not assign publicip.get() to a variable?

1 Answers1