i want to return the value of x from this function , here is the code

Question

getUD = (v) => {
    firebase
      .firestore()
      .collection("users")
      .doc(v)
      .get()
      .then((doc) => {
        let x = doc.data().name;
        console.log(x);
      });
    return "x";
  };

You can only return _a promise to the value of `x`_, not the value itself. — CherryDT, Aug 12 '20 at 09:57

score 0 · Answer 1 · answered Aug 12 '20 at 09:56

0

Try like this

getUD = (v) => {
  return firebase
    .firestore()
    .collection("users")
    .doc(v)
    .get()
    .then((doc) => {
      return doc.data().name;
    });
};

answered Aug 12 '20 at 09:56

brk

48,835
10
56
78

@KorenHamra this is because the `getUD` function is itself asynchronous and returns a promise. You need to use `then()` or `async/await` when you call it. – Renaud Tarnec Aug 12 '20 at 12:39
got it ! thanks (; – Koren Hamra Aug 12 '20 at 17:54

score 0 · Answer 2 · answered Aug 12 '20 at 09:57

getUD = async (v) => {
  const doc = await firebase
    .firestore()
    .collection("users")
    .doc(v)
    .get();
  return doc.data().name;
};


getUD = (v) => {
  return firebase
    .firestore()
    .collection("users")
    .doc(v)
    .get()
    .then((doc) => {
      return doc.data().name;
    });
};

You can simply use async/ await or return from your then.

i want to return the value of x from this function , here is the code

2 Answers2