1

I have looked through few questions regarding nested dictionary such as link_a, link_b, and link_c. But i cant seem to find the solution (or i couldnt figure it out). So i already have a dictionary which is in this format:{'key_01': ['value1', 'value2'], key_02: ....} which goes until key_08 where certain keys have different amount of 'value' in them.

For each value1 and value2 has 2 more additional values which are x and y in which i will obtain once i run my program.

So the final output that i want it as below:

{'key_01': 
   ['value1' : 
     ['x': 2], 
     ['y': 3]], 
   ['value2': 
     ['x': 2], 
     ['y': 3]], ....}

This is one of the method i tried by using this tutorial for adding into dictionary:

x = 5
for i in range(len(demo_dict['key_01'])):
    for val in demo_dict['key_01']:
        demo_dict['key_01'][0] = x

But it changed the value1 to 5 which is not what i want. And i know i cannot use append. Now im stuck.

ihaveaquestion
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2 Answers2

1

I believe you need

data = {'key_01': ['value1', 'value2'], key_02: ....} 
result = {}
for k, v in data.items():
    for i in v:
        result.setdefault(k, {}).update({'v': {'x': x, 'y': y}})

Output:

{'key_01': {
    'v': {
        'x': x, 
        'y': y
        }
    }
}
Rakesh
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0

every pair of 'key':value should be in a dictionary, like:

dict = {'key_01':[
          {'value1':{'x': 2,'y': 3}, 
           'value2':{'x': 2,'y': 3}, 
           'value3': ....]}

So key_01 has a list of dictionaries value1,value2,value3, where each has a dictionary for x and y.

this way you can access the 'x' and 'y' values as

dict['value_01']['value1']['x'] and dict['value_01']['value1']['x']
Herbert Martins Cardozo
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  • Ive made a little research regarding dict in a dict and seems like i got the format that i want. but it seems to not append the second value (value2). i'll share my code in the update. – ihaveaquestion Aug 27 '20 at 06:34