Java and skipping a level with super

Question

Possible Duplicate:
Why is super.super.method(); not allowed in Java?

If you have a class that derives from a class that derives from another is there anyway for me to call the super.super method and not the overridden one?

class A{
    public void some(){}
} 

class B extends A{
    public void some(){}
} 

class C extends B{
    public void some(){I want to call A.some();}
}

score 5 · Answer 1 · edited May 23 '17 at 10:34

5

See: Why is super.super.method(); not allowed in Java?

edited May 23 '17 at 10:34

Community

1
1

answered Jun 15 '11 at 18:28

Todd Gamblin

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score 3 · Answer 2 · answered Jun 15 '11 at 18:31

@tgamblin is right but here is a workaround :

class A{
    public void some(){ sharedCode() }
    public final void someFromSuper(){ sharedCode() }

    private void sharedCode() { //code in A.some() }
} 

class B extends A{
    @Override
    public void some(){}
} 

class C extends B{
    @Override
    public void some(){
     //I want to call A.some();
     someFromSuper();
    }
}

Create a second version of your method in A that is final (not overridable) and call it from C.

This is actually a poor design, but sometimes needed and used inside JDK itself.

Regards, Stéphane

Java and skipping a level with super

2 Answers2