I have the following list, which was created from a file:
scores=["bob.21","jeff.46","michael.75","david.12"]
How can I sort items of this list based on the integer within each item?
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2(Dupe of) [How to sort with lambda in Python](https://stackoverflow.com/questions/3766633/how-to-sort-with-lambda-in-python) + some string parsing – hnefatl Aug 31 '20 at 13:37
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It does, thank you so much! – Awesome Guy Aug 31 '20 at 13:39
2 Answers
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Use a key function that parses out the integer:
scores.sort(key=lambda x: int(x.partition('.')[2]))
That just logically sorts it as if the values were [21, 46, 75, 12] while preserving the original values.
ShadowRanger
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1@timgeb: Not when they're all two digits long (though it's harmless to convert, and might make the comparisons infinitesimally faster). But it's absolutely necessary if there might be a different number of digits. `20 < 3` is false, but `'20' < '3'` is true. – ShadowRanger Aug 31 '20 at 13:40
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scores = ["bob.21","jeff.46","michael.75","david.12"]
sorted_scores = sorted(scores,key=lambda s: int(s.split('.')[1]))
print(sorted_scores)
output
['david.12', 'bob.21', 'jeff.46', 'michael.75']
balderman
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