While loop not executing code in correct order in C

Question

i am new to learning C language . I have shifted from C++ and was implementing the while and do while loop

The following is a snippet from my code . This works fine in C++ but in C after executing while loop once it executes scanf first and then prints the menu and i am not able to figure it. Kindly help

#include <stdio.h>

int main() {
    int ch;
    char ans='y';
    while(ans=='y'){
        
        printf("\n1. Insert / Create linked list ");
        printf("\n2. Insert at specific position ");
        printf("\n3. Display ");
        printf("\n4. Search element");
        printf("\n5. Delete element");
        printf("\n6. Exit");
        printf("\nEnter choice \n");
        
        scanf("%d",&ch);
      
        switch(ch)
        {
            case 1 :
                break;
                
            case 2 :
                break;
            
            case 3 :
                break;
                
            case 4 :
                break;
                
            case 5 :
                break;
                
            case 6 :
                break;
        }
        
        printf("\nDo you want to continue ?\n");
        scanf(" %c ",&ans);
        printf("\n");
     };
    
    return 0;
}

Trailing blanks in `scanf()` format strings are dire — doubly so when the input is supposed to be interactive. You have to type some character that is not white space after the input of the number — so the user must guess/know what the next input should be before the current input (the `scanf(" %d ", &ch);` will terminate. — Jonathan Leffler, Sep 01 '20 at 05:06

score 2 · Answer 1 · answered Sep 01 '20 at 05:02

2

scanf(" %c ",&ans); --> scanf(" %c",&ans); Drop trailing space.

No need to look for white-space after ans.

answered Sep 01 '20 at 05:02

chux - Reinstate Monica

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While loop not executing code in correct order in C

1 Answers1