Why Do I Get 'None' After Reverse()

Question

Why do I get 'None' after I execute this code:

list_1 = ['a', 'b', 'c']

list_2 = list_1.reverse()

print(list_2)

Thank you.

`list_1.reverse()` is an inplace operation, which mean it modifies the existing list object instead of creating a new one — Abdul Niyas P M, Sep 02 '20 at 13:49
I know that but I don't understand why I can't reference list_1's new arrangement to list_2 — Frenk Frenk, Sep 02 '20 at 13:50
either don't create a new list and just use `list_1.reverse()` or create the new list by `list(reversed(list_1))` — Asocia, Sep 02 '20 at 13:50

score 1 · Answer 1 · edited Sep 02 '20 at 13:57

1

list_1.reverse() returns None, but instead it reverses list_1 itself.

In order to get a reversed result of list_1, you should do like this:

list_1 = ['a', 'b', 'c']

list_2 = list_1.copy()
list_2.reverse()

print(list_2)

edited Sep 02 '20 at 13:57

Zephyr

answered Sep 02 '20 at 13:51

Ahmed Mamdouh

1 Answers1