Regex find number followed by any character (comma, dot, exclamation mark) (Java has

Question

I have the following strings where I would like to identify numbers, that can be sometimes followed by any character. For example:

I should be able to find 10 and 3 in each of these strings.

I tried s.matches("[0-9,.@!]+")) but in this case I don't catch numbers not followed by special characters.

Maybe all you need is [How to extract numbers from a string and get an array of ints](https://stackoverflow.com/questions/2367381/how-to-extract-numbers-from-a-string-and-get-an-array-of-ints?) — Wiktor Stribiżew, Sep 02 '20 at 20:43

score -1 · Answer 1 · answered Sep 02 '20 at 20:47

-1

Can you use the below?

s.matches("\d+")

answered Sep 02 '20 at 20:47

Mohamad.K

score -1 · Answer 2 · answered Sep 02 '20 at 20:51

-1

maybe try

s.matches("[0-9].?");

. is any character

? is zero or more

answered Sep 02 '20 at 20:51

Ela Łabaj

2 Answers2