Suppose I have a path like C:\\exportDir\\testing\\content\\catalog\\root\\shared\\First\\First_content\\Report1
How can I retreive the child filename in my case Report1 without using split by \\
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kavya
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1This is answered here https://stackoverflow.com/questions/3925096/how-to-get-only-the-last-part-of-a-path-in-python – go2nirvana Sep 14 '20 at 09:44
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use os.listdir(folder_name), will get a list of file names from path – IVI Sep 14 '20 at 09:46
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Yes.
Use os.path.split()
Example:
import os
# path
path = '/home/User/Desktop/file.txt'
# Split the path in
# head and tail pair
head_tail = os.path.split(path)
# print head and tail
# of the specified path
print("Head of '% s:'" % path, head_tail[0])
print("Tail of '% s:'" % path, head_tail[1], "\n")
balderman
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Using [`pathlib`](https://docs.python.org/3/library/pathlib.html) is much more sympathetic than `os.path` and is as easy as doing `pathlib.Path(path).name` – Tomerikoo Sep 14 '20 at 10:00