JQuery Append to a child element

Question

I have a jQuery like this.

$.each($(".fc-daygrid-day "), function (key, val) {
  var dateYMD = $(this).attr("data-date");
  console.log(this); 
  $(this).append(`<div class="fc-dailytotal" id='dailytotal-" + dateYMD + "'></div>`);
});

Which returns something like this. ( this is what I get when I console.log(this) )

<td class="fc-daygrid-day fc-day fc-day-thu fc-day-future fc-day-other" data-date="2020-11-05">
  <div class="fc-daygrid-day-frame fc-scrollgrid-sync-inner"> <!-- line 2 -->
    <div class="fc-daygrid-day-top"><a class="fc-daygrid-day-number">5</a></div>
    <div class="fc-daygrid-day-events"></div>
    <div class="fc-daygrid-day-bg"></div>
  </div>
  <div class="fc-dailytotal" id="dailytotal-&quot; + dateYMD + &quot;">0</div> <!-- line 1 -->
</td>

I want to append the line 1 inside the line 2 div tag ? final result i want is as following. Thank you. (i am new to JQuery)

<td class="fc-daygrid-day fc-day fc-day-thu fc-day-future fc-day-other" data-date="2020-11-05">
  <div class="fc-daygrid-day-frame fc-scrollgrid-sync-inner"> <!-- line 2 -->
    <div class="fc-daygrid-day-top"><a class="fc-daygrid-day-number">5</a></div>
    <div class="fc-dailytotal" id="dailytotal-&quot; + dateYMD + &quot;">0</div> <!-- line 1 -->
    <div class="fc-daygrid-day-events"></div>
    <div class="fc-daygrid-day-bg"></div>
  </div>
</td>

Rory McCrossan · Accepted Answer · 2020-10-05T09:43:38.420

You can use find() to target the child element and then after() to insert the content to be displayed directly below it. Also note that your string concatenation syntax is incorrect. As you're using a template literal you need to use ${foo} to insert the value in to the string. Try this:

$.each($(".fc-daygrid-day"), function (key, val) {
  var dateYMD = $(this).attr("data-date");
  $(this).find('.fc-daygrid-day-top').after(`<div class="fc-dailytotal" id='dailytotal-${dateYMD}'></div>`);
});

In addition it's worth noting that the code can be improved. Firstly use data() to read a data attribute so that the result is more strongly typed. Also, given what you're actually attempting to achieve you don't need an explicit each() loop at all. You can provide a function to after() which generates the content dynamically.

$('.fc-daygrid-day .fc-daygrid-day-top').after(function() {
  let dateYMD = $(this).closest('.fc-daygrid-day').data('date');
  return `<div class="fc-dailytotal" id="dailytotal-${dateYMD}">Example: ${dateYMD}</div>`
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table>
  <tbody>
    <tr>
      <td class="fc-daygrid-day fc-day fc-day-thu fc-day-future fc-day-other" data-date="2020-11-05">
        <div class="fc-daygrid-day-frame fc-scrollgrid-sync-inner">
          <div class="fc-daygrid-day-top"><a class="fc-daygrid-day-number">5</a></div>
          <div class="fc-daygrid-day-events"></div>
          <div class="fc-daygrid-day-bg"></div>
        </div>
      </td>
    </tr>
    <tr>
      <td class="fc-daygrid-day fc-day fc-day-thu fc-day-future fc-day-other" data-date="2021-12-15">
        <div class="fc-daygrid-day-frame fc-scrollgrid-sync-inner">
          <div class="fc-daygrid-day-top"><a class="fc-daygrid-day-number">10</a></div>
          <div class="fc-daygrid-day-events"></div>
          <div class="fc-daygrid-day-bg"></div>
        </div>
      </td>
    </tr>
  </tbody>
</table>

Thank you for ur reply. this sloved my problem. thank you. also can i use `find('.fc-daygrid-day-top.fc-daygrid-day-top')` somthing like this to access `fc-daygrid-day-top` div ? — Hansaka Sandaruwan, Oct 05 '20 at 09:53
You can use any valid CSS selector to find the element. The one in your comment wouldn't work though, as you've repeated the same class twice. — Rory McCrossan, Oct 05 '20 at 09:56
ohh my bad there..thank you very much i slove my issue and learn few more things about jquery. thank you again — Hansaka Sandaruwan, Oct 05 '20 at 09:59

score 1 · Answer 2 · answered Oct 05 '20 at 09:34

Instead of using append, you just need to use prepend:

$.each($(".fc-daygrid-day"), function (key, val) {
  var dateYMD = $(this).attr("data-date");
  $(this).prepend(`<div class="fc-dailytotal" id='dailytotal-" + dateYMD + "'>prepending</div>`);
});

prepend will insert the new node before the first child of the element you are adding to, whereas append inserts it after the last child. Ref: MDN Docs for prepend

Working Example:

$.each($(".fc-daygrid-day"), function (key, val) {
  var dateYMD = $(this).attr("data-date");
  $(this).prepend(`<div class="fc-dailytotal" id='dailytotal-" + dateYMD + "'>ADDED</div>`);
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table><tr>
<td class="fc-daygrid-day fc-day fc-day-thu fc-day-future fc-day-other" data-date="2020-11-05">
  <div class="fc-daygrid-day-frame fc-scrollgrid-sync-inner"> <!-- line 2 -->
    <div class="fc-daygrid-day-top"><a class="fc-daygrid-day-number">5</a></div>
    <div class="fc-daygrid-day-events"></div>
    <div class="fc-daygrid-day-bg"></div>
  </div>
</td>
</tr></table>

JQuery Append to a child element

2 Answers2