I have this code , i need output x variable as double (3.14) without changing anything in the main function
#include <iostream>
int main() {
int x = 3.14;
std::cout << x << "\n";
return 0;
}
What should i do ?
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Alexander
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the value of `x` is `3`. You can write `std::cout << x << ".14";` Whats the point of this exercise? – 463035818_is_not_an_ai Oct 07 '20 at 08:54
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no) i can't change anything , even std::cout – Alexander Oct 07 '20 at 08:55
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You could overwrite the int() operator, but I don't see why anyone would do that – Ivan Oct 07 '20 at 08:55
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3this question makes no sense. You cannot change the output without changing the code – 463035818_is_not_an_ai Oct 07 '20 at 08:55
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you can add code before main? – 463035818_is_not_an_ai Oct 07 '20 at 08:55
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The point is make something (maybe) outside of the main to output 3.14, and do not change any symbol of code inside main – Alexander Oct 07 '20 at 08:56
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2there's something missing here, doing something like `#define int double` is undefined behavior, you aren't allowed to redefine keywords. – PeterT Oct 07 '20 at 08:56
1 Answers
1
There are two solutions, one correct and one your professor probably wants.
The correct solution (one method, there are other similar ones).
Add this right after the#includeline:int main() { double x = 3.14; std::cout << x << "\n"; return 0; } #if 0Add this at the end of the file:
#endifThe incorrect solution for your professor.
Add this line beforemain:#define int double- Why is this incorrect? Because
#defineing a reserved word is undefined behaviour.
[macro.names] A translation unit shall not #define or #undef names lexically identical to keywords [...]
- Why do I think your professor probably wants this? Because I've seen a few C++ assignments, and observed that their authors all too often disregard and abuse the C++ standard.
- Your professor might want the first solution instead. I have no way to predict that.
- Why is this incorrect? Because
n. m. could be an AI
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