Python - Condition and Loops

Question

Here is my code:

spam = input()


if spam == 1:
 print("Hello Word")
if spam == 2:
 print("Howdy")
else:
 print("Greetings")
    

#Task if spam == 1 then print Hello World if spam == 2 print Howdy and if
#anything else print greeetings

However my code is printing greetings on any input.

`input` will always return a string. Try comparing `spam == '1'` and `spam == '2'`. — rassar, Oct 08 '20 at 20:02

jaabh · Answer 1 · 2020-10-08T20:06:34.677

1

Since input() accepts string, you could cast the variable into an int to compare:

spam = input()

if int(spam) == 1:
    print("Hello World")
elif int(spam) == 2:
    print("Howdy")
else:
    print("Greetings")

edited Oct 08 '20 at 20:06

answered Oct 08 '20 at 20:05

jaabh

815
6
22

`else if` is not valid syntax. – alani Oct 08 '20 at 20:06
Thank you, I was thinking of the wrong language – jaabh Oct 08 '20 at 20:07
1

Yes I guessed you'd probably been writing a lot of C (or similar) recently :) – alani Oct 08 '20 at 20:08
c# and c++ mostly – jaabh Oct 08 '20 at 20:08

score 0 · Accepted Answer · answered Oct 08 '20 at 20:03

0

try using elif (else if)

spam = input()


if spam == '1':
 print("Hello Word")
elif spam == '2':
 print("Howdy")
else:
 print("Greetings")

answered Oct 08 '20 at 20:03

Barzuka

41
1
6

You should also make it clear that `spam` is a string and needs to be compared to one. – Pranav Hosangadi Oct 08 '20 at 20:03

score 0 · Answer 3 · answered Oct 08 '20 at 20:03

0

Your input is formatted as a string, you have to convert it to an int with int().

bests

answered Oct 08 '20 at 20:03

QLR

1
3

score 0 · Answer 4 · answered Oct 08 '20 at 20:04

0

Change the second if to elif. The then sequence should operate as expected.

answered Oct 08 '20 at 20:04

acrobat

812
4
7

score 0 · Answer 5 · edited Oct 09 '20 at 20:20

0

you are checking if it's equal to a number not a string; input returns a string not a number.

you can fix this in two ways:

change the statement to be spam == "1"
change spam = int(input())

edited Oct 09 '20 at 20:20

Ruli

2,592
12
30
40

answered Oct 08 '20 at 20:05

Proodle

51
5

score 0 · Answer 6 · answered Oct 08 '20 at 20:08

The input you are asking the user is of type integer, but the default input type is string this can be checked by

type(spam)

what you want to do is

spam = int(input())
if spam == 1:
    print("Hello Word")
elif spam == 2:
    print("Howdy")
else:
    print("Greetings")

Python - Condition and Loops

6 Answers6