Remove empty values from dictionary

Question

I have a question regarding a dictionary in python and empty values. If I had the following dictionary

my_dict={'a':[],
 'b':[1],
 'c':[],
 'd':[]
}

How I could remove empty values [] and appending the keys in an empty list?

my_dict={
 'b':[1],
}

and empty_list=['a','c','d']. With a list I would do as follows (but there are several ways to do the same):

my_dict = list(filter(None, my_dict))

But I have realised I do not know how to do the same in a dictionary.

Hi Marcin, it answers partially. I am still not understand how to remove empty values :( — , Oct 11 '20 at 18:25
seriously, sometimes it is hard for me to understand the reason why some questions are down voted and some others (with no reproducible data, no attempt of solution, ...) are not :/ — , Oct 11 '20 at 18:43

score 1 · Answer 1 · answered Oct 11 '20 at 18:27

1

You can use a dict comprehension to remove empty values:

new_dict = {k: v for k, v in my_dict.items() if v}

Then you can use set difference to get the removed keys:

removed_keys = my_dict.keys() - new_dict.keys()

answered Oct 11 '20 at 18:27

a_guest

score 0 · Accepted Answer · answered Oct 11 '20 at 18:26

0

Just do two explicit iterations for a clean solution -- first calculate the empty_list, then filter down my_dict:

empty_list = [k for k, v in my_dict.items() if len(v) == 0]
my_dict = {k: v for k, v in my_dict.items() if len(v) != 0}

answered Oct 11 '20 at 18:26

Cihan

2 Answers2